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21:11 Jul 23, 2008 |
Japanese to English translations [PRO] Tech/Engineering - Automotive / Cars & Trucks | |||||||
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| Selected response from: Katalin Horváth McClure United States Local time: 02:04 | ||||||
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Summary of answers provided | ||||
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4 +4 | Put in 2 x the necessary amount of coolant required for half the capacity of the system |
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Discussion entries: 2 | |
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Put in 2 x the necessary amount of coolant required for half the capacity of the system Explanation: I think they are saying B. I assume there is a table or something that shows the required coolant for capacities up to 6L. I also assume that the relationship between the capacity below 6L and the required coolant volume is not linear. For 6 L capacity, you need 2L coolant, this is clear. For 8 L capacity, you take half of that capacity, which is 4L, and look up the required coolant volume in the table for 4 L capacity, then multiply by 2. For 10 L capacity, you take half of that capacity, which is 5L, and look up the required coolant volume in the table for 5 L capacity, then multiply by 2. For 12 L capacity, you take half of that capacity, which is 6L, and look up the required coolant volume in the table for 6 L capacity (this is the only thing we know from your posted sentence, this is 2L), then multiply by 2. So, for 12L capacity you would need 4 L. |
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Grading comment
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